Four capacitors with capacitances C1 = 3.5 nF, C2 = 2.1 nF, C3 = 1.3 nF, and C4

Question

Four capacitors with capacitances C1 = 3.5 nF, C2 = 2.1 nF, C3 = 1.3 nF, and C4 = 4.9 nF are wired to a battery with V = 10.3 V, as shown. What is the equivalent capacitance of this set of capacitors?

Its a line with C2 C3 then C4, the 3 kind of looks like a 2

Four capacitors with capacitances C1 = 3.5 nF, C2 = 2.1 nF, C3 = 1.3 nF, and C4 = 4.9 nF are wired to a battery with V = 10.3 V, as shown. What is the equivalent capacitance of this set of capacitors? Its a line with C2 C3 then C4, the 3 kind of looks like a 2 The answer is 4.3nF i think but im not sure, If you could also show work that would be awesome!! Thanks in advance!!

Explanation / Answer

First, C3 and C4 are in parallel

So C3,4 = C3 + C4

C3,4 = 1.3 + 4.9 = 6.2 nF

That 6.2 nF is in series with C1

So the equivalent capacitance of C1,3,4 =

1/C1,3,4 = 1/C1 + 1/C3,4

1/C1,3,4 = 1/3.5 + 1/6.2

C1,3,4 = 2.24 nF

Finally, the C1,3,4 is in parallel with C2

The Final CEQ = C1,3,4 + C2

CEQ = 2.24 + 2.1

CEQ = 4.34 nF

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