330 cm3 of water at 88°C is mixed with 110 cm3 of water at 4°C. Calculate the fi

Question

330 cm3 of water at 88°C is mixed with 110 cm3 of water at 4°C. Calculate the final equilibrium temperature, assuming no heat is lost to outside the water. Then Imagine now that one tried to repeat the same measurement, but between the time that the 330 cm3 of water was measured at 88°C and the time it was mixed with the 110 cm3 of water at 4°C, the warmer water had lost 1980 cal to the environment. Calculate the final equilibrium temperature assumning no heat loss after mixing occurs.

Thank you!

Explanation / Answer

density of water = 1000kg/m^3

330cm^3=0.33kg

110cm^3=0.11kg

Cwater=4186 J/kg

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