A microscope is a device where a first lens makes a real image of an object, and
ID: 2039276 • Letter: A
Question
A microscope is a device where a first lens makes a real image of an object, and that real image is then viewed with a second lens used as a magnifying glass to make a virtual image that is enlarged The picture shows the two converging lenses of a compound microscope: the objective lens (on the left) near which the object to be viewed is placed, and the eyepiece lens (on the right) which functions as the magnifying glass. The objective lens has a focal length fobj (with focal points indicated by an "x"), the eyepiece lens has a focal length feye (with focal points indicated by an "o"), and the two lenses are separated by a distance L. The picture may not be to scale, but it will at least allow you to correctly determine the kinds of images formed by each lens. A. The image formed by the objective lens is ( real ) and (inverted B. We use the image formed by the objective lens as the object for the eyepiece lens. The eyepiece lens then forms its own image. This image formed by the eyepiece lens is a Virtual image. For the eyepiece lens to form this kind of image, what must be true about the location of the image formed by the objective lens? This answer has not been graded yet. C. The distance between the lenses is L 13 cm, and the focal lengths are fobj objective lens. What is the image distance of the objective lens image? obj cm and feye 8 cm. The object to be viewed, a cell, is placed a distance of 1.222 cm in front of the CT D. How far is the objective lens image from the eyepiece lens? cm eye E. What is the magnitude of the distance between the eyepiece lens and the image that it forms? cm eye Is the image formed by the eyepiece lens to the left or the right of the eyepiece lens? left F. What is the magnification due to each individual lens? Mphi obj eye G. The total magnification is the product of the magnification due to each individual lens, and it is the ratio of the final image height over the original object height. If you are viewing a cell with a size of 10 ?m, what is the size (absolute value) of the image that you view by looking through the eyepiece? size-Explanation / Answer
B)
The image formed by the objective lens must be formed in between the two lenses at distance from eyepiece which is smaller than the focal length of eyepiece .
C)
for the objective lens :
f = 1 cm
do = object distance = 1.222 cm
di = image distance
using the lens equation
1/di + 1/do = 1/f
1/di + 1/1.222 = 1/1
di = 5.505 cm
D)
Oeye = 13 - 5.505 = 7.495 cm
E)
for the eyepiece lens :
f = 8 cm
do = 7.495 cm
di = image distance =?
using the lens equation
1/di + 1/do = 1/f
1/di + 1/7.495 = 1/8
di = - 118.73 cm
|ieye| = 118.73 cm
left
F)
mobj = - di/do = -5.505/1.222 = - 4.505
meye = - di/do = - (- 118.73 )/7.495 = 15.84
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