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Work on Incline at 22° to the horizontal, a worker exerts a force of 410 N paral

ID: 2039197 • Letter: W

Question

Work on Incline at 22° to the horizontal, a worker exerts a force of 410 N parallel to the Indine. The To push a 44-kg crate up a frictionless incline What work is done on the crate by the worker? mýs crate moves a distance of 1.4 m. A: 4325B: 574FC: 7630D: 1.02 x10 Submit Arswe Tries 0/1 What work is done on the crate by the weight of the crate? (use g- 10 m/s?) A:-231 CB: -307 OC:-408OD:-543 Subit Answe Tries 0/1 What work is done by the normai force exerted by the floor on the crate? AO:26.C 354 D: 47. Sotmit Answer Tries / What is the total work done on the crate? A: 343 B: 457 C: 607 D: 806 ubmt Answer Tries 0/1

Explanation / Answer

Work done , W = F.d (dot product)

W = F d cos(theta)


F = 410 N, d = 1.4 m and theta = 0

W = 410 x 1.4 x 1 = 574 J .....Ans

Ans(B)


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F = (44 x 10) = 440 N , d = 1.4 m

theta = 90 + 22

W = (440)(1.4) (-sin22) = - 231 J .....Ans

Ans(A)


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for normal force, theta= 90 deg

cos90 = 0

W = 0

Ans(A)


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total work done = 574 - 231 + 0 = 343 J  

Ans(A)

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