8) Given the vectors A 71 - 6j and B 4T+10j a) Calculate the dot product of the

Question

8) Given the vectors A 71 - 6j and B 4T+10j a) Calculate the dot product of the vectors b) Calculate the angle between the two vectors max 0 6.0 ms 2000 N 9) Given the impulse graph to the above and F a) What is magnitude of the impulse? b) This impulse corresponds to a tennis ball being hit with a racquet. The ball's initial velocity is 20 m/s to the left (negative) and it has a mass of 200 g. What is its velocity after being hit? 10) Bill sees a cart 8.0 m in front of him. He decides to run to the cart as fast as he can, jump on it, and roll down the road. Bill has a mass of 75 kg and the cart has a mass of 25 kg. If Bill accelerates at a constant 1.0 m/s2, what is the speed of the cart after Bill jumps on? Before: After x 8.0 m System (V1x)B System (orB 0 m/s a 10m/s2 mB 75 kg 0 m 8m mc = 25 kg Find: V2r

Explanation / Answer

8) A = 7i - 6j

B = 4i + 10j

(A) dot product = A.B

= (7 x 4) + (-6 x 10)

= - 32

(B) A.B = |A| |B| cos(theta)

|A| = sqrt(7^2 + 6^2) = sqrt(85)

|B| = sqrt(4^2 + 10^2) = sqrt(116)

- 32 = sqrt(85) sqrt(116) cos(theta)

cos(thets) = - 32 /sqrt(9860) = - 0.322

theta = 109 deg ....Ans

Related Questions

Navigate

• Browse (All)
• Browse 8
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.