Two long, parallel conductors, separated by 13.0 cm, carry currents in the same

Question

Two long, parallel conductors, separated by 13.0 cm, carry currents in the same direction. The first wire carries a current 116.00 A, and the second carries I29.00 A. (See figure below. Assume the conductors lie in the plane of the page.) (a) What is the magnetic field created by I at the location of I2? direction (b) What is the force per unit length exerted by i1 on 12? What Is the equation giving the magnetic force on a current carrying wire? N/m direction (c) What is the magnetic field created by 12 at the location of 1 magnitude directionSelect- (d) What is the force per length exerted by I2 on 1? magnitude N/m Select-

Explanation / Answer

a) B = uoI1 / 2*pi*r

B = 4*pi*10-7*6 / 2*pi*0.13

B = 9.231E-6 T

B = 9.231 uT (perpendicular to I and r)

b) We know, F = ILB

So, F/L = IB

F/L = uoI1I2 / 2*pi*r

F/L = 4*pi*10-7*6 / 2*pi*0.13

F/L = 7.384E-5 N/m

c) B = uoI2 / 2*pi*r

B =  4*pi*10-7*8 / 2*pi*0.13

B = 12.31 uT or 1.231e-5 T

d) F/L = uoI2I1 / 2*pi*r

F/L = 7.384e-5 N/m

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