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Two long straight thin wires with current lie against an equally long plastic cy

ID: 1431750 • Letter: T

Question

Two long straight thin wires with current lie against an equally long plastic cylinder, at radius R = 21.4 cm from the cylinder's central axis. Figure (a) shows, in cross section, the cylinder and wire 1 but not wire 2. With wire 2 fixed in place, wire 1 is moved around the cylinder, from angle ?1 = 0° to angle ?1 = 180°, through the first and second quadrants of the xy coordinate system. The net magnetic field at the center of the cylinder is measured as a function of ?1. Figure (b) gives the x component Bx of that field as a function of ?1 (the vertical scale is set by Bxs = 6.5 ?T), and Figure (c) gives the y component By (the vertical scale is set by Bys = 4.3 ?T). (a) At what angle ?2 is wire 2 located? (assume that angle ?2 lays in the range from -180° to 0°) What are the (b) magnitude and (c) direction (into or out of the page) of the current in wire 1 and the (d) magnitude and (e) direction (into or out of the page) of the current in wire 2?

Wirel 180° 180°

Explanation / Answer

part a ) there is no y compont of magnetic field from wire 1 , the total ycomponet of magnetic field is zero . means wire 2 either at 90 degree or -90 degree .

wire 2 must be at -90 degree , the bottom of the cylinder . it would pose an obstacle for the motion of wire 1 if it were anywhere in the top semicircle .

part b )

looking at theta = 90 degree Bnetx = maximum (6.5 muT )

conclude that B1x = 6.5 - 2.167 = 4.33 muT

i1 = 2pi*R*B1x/uo =

i1 = 0.214 * 4.13 x 10^-6 / 2*10^-7

i1 = 4.4191 A

part c )

current is out of the page

part d ) we note that there is no x component of magnetic field from wirewhen theta1 = 0

so B2x = 2.167 muT

i2 = 2pi*RB2/uo = 2.31869 A

part e )

current is into the page

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