A capacitor with capacitance C is connected to a battery until charged, then dis

Question

A capacitor with capacitance C is connected to a battery until charged, then disconnected from the battery. A dielectric having constant ? is inserted in the capacitor.

What changes occur in the charge, potential and stored energy of the capacitor after the dielectric is inserted?
---Select--- V stays same, Q increases, U increases V stays same, Q decreases, U stays same V increases, Q decreases, U increases V decreases, Q stays same, U decreases none of the above cannot be determined

#2

The diagram shows a circular wire loop of radius R carrying current I.

3#

4#

(a) What is the magnitude of the electric field?
N/C

(b) What are the magnitude and direction of the electrostatic force Fel exerted on a proton placed in this field?
N   ---Select--- upward, downward,, leftward, rightward ,

(c) What is the magnitude of the gravitational force Fg on the proton?
N

(d) What is the ratio Fel / Fg in this case?

Explanation / Answer

After disconnected capacitor, harge can neither leave nor appear on the plates, it means cahrge Q remains the same ever after inserting the dielectric. ------   Q stays same

capacitance of a capacitor will increase after the insertion of Dielectric . Again, C = Q/V. it means the V decreases as C increases ------- V decreases

Capacitance increases and the charge remains constant, the energy stored U = Q^2 / 2C. it means as capacitance increases, energy stored reduces. ------- U decreases

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