iscms/mod/ibis/view.php?id-4620587 Print Calculetor Periodic Table n 1 of 25 Inc

Question

iscms/mod/ibis/view.php?id-4620587 Print Calculetor Periodic Table n 1 of 25 IncorrectIncorrect Map Sapling Learning A brave child decides to grab on to an already spinning merry a mass of 28.5 kg. The child grabs causing the angular velocity of the m moment of inerti The child is initially at rest and has s and dings to a bar that is 1.35 m from the center of the go-round to abruptly drop from 55.0rpm to 19.0 rpm. What is the a of the merry-go-round with respect to its central axis? Number kg m Give Up & View Soludion Check Answer NextEx ? Hint SAMSUNG

Explanation / Answer

Here ,

m = 28.5 Kg

r =1.35 m

initial angular speed , wi = 55 rpm = 5.75 rad/s

final angular speed, wf = 19 rpm = 1.98 rad/s

let the moment of inertia of the merry go round is I

Using conservation of angular momentum

(m * r^2 + I ) * wf = wi * I

(28.5 * 1.35^2 + I ) * 1.98 = 5.75 * I

solving for I

I = 27.28 Kg.m^2

the moment of inertia of the merry go round is 27.28 Kg.m^2l

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