b Order the following elements from most atoms in 1 g at the top to fewest atoms

Question

b

Order the following elements from most atoms in 1 g at the top to fewest atoms in 1 g at the bottom.

Most atoms                        [ Select ] ["beryllium", "magnesium", "strontium", "calcium"] Second most atoms                        [ Select ] ["magnesium", "beryllium", "strontium", "calcium"] Second fewest atoms                        [ Select ] ["beryllium", "magnesium", "calcium", "strontium"] Fewest atoms                        [ Select ] ["beryllium", "calcium", "strontium", "magnesium"]

Explanation / Answer

Number of atoms = (mass/atomic mass)*No

Here No is avagadro number = 6.022*10^23

For beryllium ,

Number of atoms (n) = (1/9)*6.022*10^23 = 6.69*10^22

For magnesium ,

Number of atoms (n) = (1/24)*6.022*10^23 = 2.51*10^22

For calcium ,

Number of atoms (n) = (1/40)*6.022*10^23 = 1.51*10^22

For strontium ,

Number of atoms (n) = (1/87)*6.022*10^23 = 6.922*10^21

From the above ,

Most atoms - beryllium

Second most atoms - magnesium

Second fewest atoms - calcium

Fewest atoms - strontium

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