Linear Momentum (Ch 9) Problem 9.24 A 0.052-kg pet lab mouse sits on a 0.35-kg a

Question

Linear Momentum (Ch 9) Problem 9.24 A 0.052-kg pet lab mouse sits on a 0.35-kg air-track cart, as shown in (Figure 1). The cart is at rest, as is a second cart with a mass of 025 kg. The lab mouse now jumps to the second cart. After the jump. the 0 35-kg cart has a speed of vi 0.86 m/s ? Part A What is the speed u2 of the mouse and the 0 25-kg cart? Express your answer to two significant figures and include appropriate units Figure of 1 0.35 kg 0.25 kg (a) Before the jump 0.35 kg 0.25 kg (b) After the jump 0???

Explanation / Answer

let v is the speed of rabit after jumping from first cart.

using conservation of momemtum

0.052*v = 0.35*0.86

v = 0.35*0.86/0.052

= 5.79 m/s

now apply conservation of momentum after the rabit jumps to second cart

(0.052 + 0.25)*v2 = 0.052*5.79

v2 = 0.052*5.79/(0.052 + 0.25)

= 1.0 m/s <<<<<<<<----------------Answer

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