Linear Math. Please I would like a step by step solution. Ex.1 Ex.2 An oil refin

Question

Linear Math.

Please I would like a step by step solution.

Ex.1

Ex.2

An oil refinery produces low-sulfur and high-sulfur fuel. Each ton of low-sulfur fuel requires 5 minutes in the blending plant and 4 minutes in the refining plant, each ton of high-sulfur fuel requires 4 minutes in the blending plant and 2 minutes in the refining plant. If the blending plant is available for 3 hours and the refining plant is available for 2 hours, how many tons of each type of fuel should be manufactured so that the plants are fully utilized?

Explanation / Answer

Solution 1.

let x be the number of tons of low sulphur

and y be the number of tons of high Sulphur

then as we have been given that

Each ton of low-sulfur fuel requires 5 minutes blending plant

thus total time required by by x low sulphur = 5x

and total time required by the low sulphur in refining plant is = 4x

Similarily for high sulphur

time for blending plant = 4y

and time required fo the refining plant = 2y

now total number of minutes required in blending = 5x+4y

and the given blending time is 3 hours that is = 180 minutes!

so we have

5x+4y =180 ................(1)

similarly we have another equation

4x + 2y = 120 ............ (2)

so all we need to do is solve these two equations

we get x =20 and y = 20

thus we can produce 20 tons of each for efficient working.

Solution 2.

Similar to solution of part 1 we will make two equations and solve them to get our result.

Equations formed will be as below

2x + 2y = 8

5x + 3y = 15

Solving both equations will give x = 3/2 and y= 5/2 thus 3/2 tons of regular plastic and 5/2 tons of special plastic can be made daily

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.