C Spire LTE 11:20 PM blackboard.alcorn.edu Multiple Attempts This test allows mu

Question

C Spire LTE 11:20 PM blackboard.alcorn.edu Multiple Attempts This test allows multiple attempts. Force Completion This test can be saved and resumed later v Question Completion Status: QUESTION 1 10 points Save Answer A heater of total resistance 80 is connected to 50 V a) Find the current that flows through the heater is 23A b) 3125 W will it take to heat a room from 10.0°C to 25.0°C if the heater consums 7.79 x 10J ? d)How many kilowatt-hours of electricty ulated in part (c) are used during the time calc e)What is the cost(with electrical energy at 12 cents per kWh) of running the heater

Explanation / Answer

here,

resistance , R = 8 ohm

potential difference , V = 50 V

a)

the current through the heater , I = V/R = 6.25 A

b)

the power rating , P = V * I = 312.5 W

c)

let the time taken be t

P * t = 7.79 * 10^5

312.5 * t = 7.79 * 10^5

solving for t

t = 2492.8 s = 0.69 hr

d)

the energy required , E = P * t

E = 0.312.5 * 0.69 KWH = 0.22 KWH

e)

the cost , C = E * 12 cents

C = 2.6 cents

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