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C Secure https//www.webassign nnment Responses/Mast?dep-15726322 gn.net/web/studes Displacement vector A points due east and has a magnitude of 1.se km. Displacement vector B due north and has a magnitude of 2.8 km. Displacement vector C points due points west and has a magnitude of 1.4 km. Displacement vector D points due south and has a magnitude of 1.6 km. Find the magnitude and direction (relative to due east) of the resultant vector counterclockwise om due east 5. o -2 points CJ101 P050 The magnitudes of the four placement vectors shown in the drawing are A .0 m, B 11.0 m, c 12.0 m, and D 20.0 m. Determine the magnitude and directional angle for these vectors are added together the resultant that occurs om the axis counterclockwise 35.0 na O Type

Explanation / Answer

We can write the vectors as:

A = +1.54 i ; B = +2.8 j ; C = -1.4 i ; D = -1.6 j

A + B + C + D = 1.54 i + 2.8 j - 1.4 i - 1.6j

A + B + C + D = 0.14 i + 1.2 j

So the magnitude of A + B + C + D will be:

l (A + B + C + D) l = sqrt [(0.14)^2 + (1.2)^2] = 1.21 km

Hence, l( A + B + C + D)l = 1.21 km

direction would be given by:

theta = tan-1 (1.2/0.14) = 83.35 deg

Hence, theta = 83.35 deg

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