PHYS-2325: University Physics-I Ch-10 QUIZ: CHAPTER 10 ROTATION OF A RIGID BODY
ID: 2031752 • Letter: P
Question
PHYS-2325: University Physics-I Ch-10 QUIZ: CHAPTER 10 ROTATION OF A RIGID BODY ABOUT A FIXED AXISa im tosido bno.ooli 9d1 no pnit291 2i smteldo.p:/ 00. A ? M V NAMB: 1oo ed zzelnoitont i ixo vellug edt t2e1 mort be2o9le1 2 DATE: July-24, 10-2012 tirl of i mot benUP91 lovnstni 9mit ertt etDluolD? 've A grinding wheel is in the form of a uniform solid disk of radius 12.00 cm and mass 2.50 kg. It starts from rest and accelerates uniformly under the action of the constant torque of 0.700 Nm that the motor exerts on the wheel. (a) How long does the wheel take to reach its final operating speed of 1.200 rev/min? The four particles in Figure P10.21 are connected by rigid rods of negligible mass. The origin is at the center of the rectangle. The system rotates about the y-axis. Calculate the moment of 2 o wwaxisExplanation / Answer
here,
mass , m = 2.5 kg
radius , r = 12 cm =0.12 m
constant torque , t = 0.7 N.m
let the angular accelration be alpha
t = I * alpha
0.7 = 0.5 * 2.5 * 0.12^2 * alpha
solving for alpha
alpha = 38.9 rad/s^2
final angular speed , w = 1200 rev/min = 125.6 rad/s
let the time taken be t
w = 0 + alpha * t
125.6 = 0 + 38.9 * t
solving for t
t = 3.23 s
the time taken is 3.23 s
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