A force of 11.0 N is directed downward perpendicular to the stick at Point B. Wh

Question

A force of 11.0 N is directed downward perpendicular to the stick at Point B. What is the torque from this force?

A force of 17.0 N is directed upward perpendicular to the stick at Point A. What is the torque from this force?

A force of 26.0 N is directed upward at angle 33.2° to the right of the perpendicular to the stick at Point C. What is the torque from this force?

A force of 11.0 N is applied horizontally to the right at C. What is the torque from this force?

Two forces are applied simultaneously to the stick. A force of 24.0 N is directed upward perpendicular to the stick at Point F and a force of 17.0 N is directed upward perpendicular to the stick at Point A. What is the net torque from these two forces?

Explanation / Answer

torque= r*F*sintheta

r = distance between rotation ais and point of action of force

F = magnitufde of force

theta = angle between r and F

1)

torque = rf*F*sin90

rf = 8*18 = 144 cm = 1.44 m

torque = 1.44*24*sin90 = + 34.56 Nm

2)

torque = rb*F*sin90

rb = 3*18 = 54 cm = 0.54 m

torque = -0.54*11*sin90 = -5.94 Nm

(3)

torque = ra*F*sin90

rb = 7*18 = 126 cm = 1.26 m

torque = +1.26*17*sin90 = + 21.42 Nm

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(4)

torque = rc*F*sin90

rb = 10*18 = 180 cm = 1.8 m

torque = -1.8*26*sin33.2 = - 25.63 Nm

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(5)

torque = ra*F*sin180

rb = 10*18 = 180 cm = 1.8 m

torque = -1.8*26*sin180 = 0 Nm

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(6)
net torque = + 34.56 + 21.42 = + 55.98 Nm

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DONE please check the answer. any doubts post in comment box

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