Workers have loaded a delivery truck in such a way that its center of gravity is
ID: 2027433 • Letter: W
Question
Workers have loaded a delivery truck in such a way that its center of gravity is only slightly forward of the rear axle, as shown in the figure. The mass of the truck and its contents is 6610 kg. Find the magnitudes of the forces exerted by the ground on (a) the front wheels and (b) the rear wheels of the truck.
Explanation / Answer
Let NF = force exerted by ground on front wheels
NR = force exerted by ground on real wheels
Part A : Torque at real wheels = 0
-mg.(0.63) + NF.(2.30 + 0.63) = 0
NF = mg.(0.63)/(2.93) = (6610).(9.8).(0.63)/(2.93)
NF = 13928.375 N
Part B : NF + NR = mg
NR = mg - NF = 6610.9.8 - 13928.375
NR = 50849.625 N
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.