The drawing shows an outstretched arm (0.61m) that is parallel to the floor. The

Question

The drawing shows an outstretched arm (0.61m) that is parallel to the floor. The arm is pulling downward against the ring attached to a pulley system, in order to hold the 98-N weight stationary. To pull the arm downward, the latisimus dorsi muscle applies the force M in the drawing, at a point that is 0.069m from the shoulder joint (axis of rotation) and oriented at an angle 29 degrees (below -x axis). The arm has a weight of 47N and a center of gravity that is located 0.28m from the shoulder joint. Find magnitude of M.

So I got that Fx=-Mcos29, which doesn't make sense because then M would be zero.

Then I got that Fy=-Msin29-Warm+Wweight which comes out to M=105N

Then I got that =-M*lm - Warm*larm + Wweight*lweight, which comes out to M=675N

What is the correct answer??

Explanation / Answer

I also got your answer using the sum of forces in the y direction, getting M = 105 N

you should be able to find this using the sum of torques is zero as well

your first term in  your torque equation is missing a sin 29

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