The drawing shows a uniform electric field that points In the negative y directi

Question

The drawing shows a uniform electric field that points In the negative y direction: the magnitude: of the field is 5900 N/C. A 15 mg particle with 100 nC of charge moves from B to C under the influence of this field. A different particle of same mass and charge moves from A to C within the same field. ic Potential difference between points A and B is ______ Potential difference between points B and C is ______ Potential difference between points A and C is ______ The speed gained by particle which moved from B to C ______ The speed gained by the particle which moved from A to C ______

Explanation / Answer

2. Potential difference, deltaV = -E.d

from A to B : distance is perpendicular to the field.

hence deltaV = 0

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B to C : VC - VB = (5900 N/C) (0.08) = 472 Volt .......Ans

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from A to C: VC - VA = 472 Volt

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gain in KE = q deltaV

m v^2 /2 = q deltaV

(15 x 10^-6 kg) v^2 / 2 = (100 x 10^-9 C) (472)

v = 2.51 m/s

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it will also be same. v = 2.51 m/s

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