A coaxial cable has an inner conducting wire carrying current Ii = 5.0 A and an
ID: 2017451 • Letter: A
Question
A coaxial cable has an inner conducting wire carrying current Ii = 5.0 A and an outer conducting layer carrying current Io = 10.0 A. The inner cable has a radius of 0.5 cm and the outer conducting layer has a radius of 1.0 cm. There is air in between the two conductors.
a) Using Ampere’s Law, determine the magnitude and direction of the magnetic field at a distance of 0.6 cm from the center.
b) Using Ampere’s Law, determine the magnitude and direction of the magnetic field at a distance of 1.2 cm from the center?
Explanation / Answer
The diagram is not given. (or) current directions are not given Let us assume inner conducting wire has current direction into the page outer Conducting wire has current direction out of the page (a) magnetic field B = 0I / 2r Here r = 0.006 m I = current enclosed = 0.5A B = ( 4*10-7 H /m) ( 5 A) / (2 (0.006m = 1.67*10-4 T Direction is clock wise direction (b) magnetic field B = 0I / 2r Here r = 0.012 m I = current enclosed = ( 10 A - 5A) = 5A B = ( 4*10-7 H /m) ( 0.5A) / (2 (0.012) = 0.833 *10-4T Direction is clock wise direction Here r = 0.012 m I = current enclosed = ( 10 A - 5A) = 5A B = ( 4*10-7 H /m) ( 0.5A) / (2 (0.012) = 0.833 *10-4T Direction is clock wise directionRelated Questions
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