Q1) Light of wavelength 556 nm is incident on a narrow slit. The angle between t
ID: 2015162 • Letter: Q
Question
Q1) Light of wavelength 556 nm is incident on a narrow slit. The angle between the first diffraction minimum on one side of the central maximum and the first minimum on the other side is 1.11°. What is the width of the slit?Q2) In a double-slit arrangement the slits are separated by a distance equal to 94 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum? (b) What is the distance between these maxima on a screen 51.4 cm from the slits?
please answer both questions.
Explanation / Answer
1) given taht wave length = 556 nm 2 = 1.110 = 0.5550 width of the slit a = m/ sin where m = 1 then a = 1 * 556 * 10-9 m/ sin( 0.555) = 5.74 * 10-5 m 2) Slit separation d = 94 ( a) . angular separation in radians between the centralmaximum and an adjacent maximum is then = / D = / d where = fringe width = D / d = / 94 = 1/94 = 0.0106 rad ( b ) . we know = / D = D = 0.0054484m width of the slit a = m/ sin where m = 1 then a = 1 * 556 * 10-9 m/ sin( 0.555) = 5.74 * 10-5 m 2) Slit separation d = 94 ( a) . angular separation in radians between the centralmaximum and an adjacent maximum is then = / D = / d where = fringe width = D / d = / 94 = 1/94 = 0.0106 rad ( b ) . we know = / D = D = 0.0054484m Slit separation d = 94 ( a) . angular separation in radians between the centralmaximum and an adjacent maximum is then = / D = / d where = fringe width = D / d = / 94 = 1/94 = 0.0106 rad ( b ) . we know = / D = D = 0.0054484mRelated Questions
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