A particle has a charge of +1.5 µC and moves from point A to point B, a distance

Question

A particle has a charge of +1.5 µC and moves from point A to point B, a distance of 0.18 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +5.50 10-4 J.
(a) Find the magnitude and direction of the electric force that acts on the particle. magnitude 1 N
direction perpendicular to

(b) Find the magnitude and direction of the electric field that the particle experiences. magnitude 3 N/C
direction along

Explanation / Answer

Difference in the electric potential energy=workdone=Force*displacent http://www.cramster.com/answers-sep-10/physics/finding-electric-force-particle-charge-158-microc-moves-poi_948111.aspx

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