The performance of the starter circuit in a an automobile can be significantly d
ID: 2006069 • Letter: T
Question
The performance of the starter circuit in a an automobile can be significantly degraded by a small amount of corrosion on a battery terminal. Figure 26-38a depicts a properly functioning circuit with a battery (12.5-V emf, 0,02 ohms internal resistance) attached via corrosion-free cables to a starter motor of resistance R_s = 0.15 ohms. Suppose that later, corrosion between a battery terminal and a starter cable introduces an extra series resistance of just R_c = 0.10 ohms into the circuit as suggested in figure. Let P_0 be the power delivered to the starter in the circuit free of corrosion, and let P be the power delivered to the circuit with corrosion. Determine P/P_0.FIGURE IS IN THE BOOK.
Explanation / Answer
Given emf = 12.5 V internal resistance r = 0.02 resistance R s = 0.15 R c = 0.1 current through the circuit free of corrision is I = / R + r = 12.5 / ( 0.15 +0.02 ) = 73.5294 A power delivered to the starter in the circuit free of corrosion, P = I 2 R = ( 73.5294 ) 2 ( 0.15 ) = 810.986 W corrosion between a battery terminal and a starter cable introduces an extra series resistance of just R_c R = Rc + R s = 0.1+0.15 = 0.25 current through the circuit with corrision is I = / R + r = 12.5 / ( 0.25 +0.02) = 46.2962 A power delivered to the starter in the circuit with corrosion Po =I 2 R = ( 46.2962) 2 ( 0.25 ) = 535.836W P / Po = 810.986 / 535.836 = 1.5134Related Questions
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