The percent yield of a reaction indicates the ratio of the amount of desired pro

Question

The percent yield of a reaction indicates the ratio of the amount of desired product actually recovered in a reaction to the amount of desired product predicted to be formed by the stoichiometry of the reaction multiplied by 100, or % yield (mass obtained)/(mass predicted) times 100. If in Step I, 0.673 g Cu is reacted with excess nitric acid to form 0.990 g of copper(II) nitrate, what is the percent yield of copper(II) nitrate in this reaction if, from the stoichiometry, it is known that 1.000 g Cu should form 2.952 g of copper(II) nitrate?

Explanation / Answer

Cu +    2 HNO3 ---------------> Cu(NO3)2 + H2

1.000 g                                       2.952g

0.673 g                                           ??

mass of Cu(NO3)2 formed = 0.673 x 187.56 / 63.55

                                          = 1.987 g

actual yield = 0.990 g

theoretical yield = 1.987 g

percent yield = (actual / theoretical) x 100

                     = (0.990 / 1.987) x 100

percent yield = 49.83%

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