At an intersection of hospital hallways, a con- vex mirror is mounted high on a

Question

At an intersection of hospital hallways, a con-
vex mirror is mounted high on a wall to help
people avoid collisions. The mirror has a ra-
dius of curvature of 0.739 m.

Part 1) Locate the image of a patient from 11.9 m
the mirror.
Answer in units of m.

Part 2) Find the magnification.

Part 3) Describe the image.

1. virtual, upright, smaller
2. real, upright, smaller
3. real, upright, larger
4. None of these
5. real, inverted, larger
6. real, inverted, smaller
7. virtual, inverted, larger
8. virtual, inverted, smaller
9. virtual, upright, larger

Explanation / Answer

given radius of curvature = r = -0.739m the center of curvature of convex mirroe behind the mirror as its focal length   so we set r = -0.739m so that focal length f = r/2                                   = -0.739m/2 = -0.3695m the object is infront of the mirror d0 =11.9m from the mirror eq    1/di = 1/f - 1/d0          = 1/-0.3695m - 1/11.9m       = -11.9m - 0.3695m/4.39    di = - 4.39m/12.2695 = - 0.35m magnification m = -di/ d0                           = - ( -0.35m)/ 11.9m = 0.030 image distance is negative so image is behind the mirror , image is up right and small                           = - ( -0.35m)/ 11.9m = 0.030 image distance is negative so image is behind the mirror , image is up right and small

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