A point charge q 2 = -3.8 C is fixed at the origin of a co-ordinate system as sh

Question

A point charge q2 = -3.8 C is fixed at the origin of a co-ordinate system as shown. Another point charge q1 = 1.6 C is is initially located at point P, a distance d1 = 8.4 cm from the origin along the x-axis

3)

What is the potential energy of the system composed of the three charges q1, q3, and q4, when q1 is at point R? Define the potential energy to be zero at infinity.

4)

The charge q4 is now replaced by charge q5 which has the same magnitude, but opposite sign from q4 (i.e., q5 = 1.9 C). What is the new value for the potential energy of the system?

5)

Charges q3 and q5 are now replaced by two charges, q2 and q6, having equal magnitude and sign (-3.8C). Charge q2 is located at the origin and charge q6 is located a distance d = d1 + d2 = 11.8cm from the origin as shown. What is PE, the change in potential energy now if charge q1 is moved from point P to point R?

Explanation / Answer

What is the potential energy of the system composed of the three charges q1, q3, and q4, when q1is at point R? Define the potential energy to be zero at infinity

In the comment you posted that you need the answer for the 3rd question,

So, We know that the potential energy,U=kq1q2/r

Sum all the contribution then

d2=3.4

a=2

q1=1.6 *10-6 C

q3=1.6 *10-6 C

q4=1.6 *10-6 C

U34=9*109*1.6 *10-6 C*1.6 *10-6 C/(4)=5.76*10-3 J

U14=9*109*1.6 *10-6 C*1.6 *10-6 C/(3.4)=6.776*10-3 J

U13=9*109*1.6 *10-6 C*1.6 *10-6 C/(3.4)=6.776*10-3 J

Total Potential energy=0.0193 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.