A point charge of 8 times 10^-9 C (= 8 nC) is located 2.0 meters from a point ch
ID: 1655988 • Letter: A
Question
Explanation / Answer
will answer 4 parts as per Chegg's policy:
Q.1 F = 9 x 10^9 (8 x 10^-9) (5 x 10^-9) / (4)= 90 x 10^-9 N
b) repulsive in nature
Q. 2 Between Na and Cl
F = 9 x 10^ 9 ( + 1.6 x 10^-9) ( -1.6 x 10^-9) / (0.5 x 10^-9 )^2 = 92.16 x 10^ 9 N
b) No force will remain same between
Q.3 E = 9 x 10^9 (5 x 10^-6) / (9) = 5 x 10^3 N/C
Q. 5 electric field will be 0 to the left of positive charge
K (3 x 10^-6 )/ x^2 = K (5 x 10^-6 ) / ( 1+x) ^2
3 ( x^2 + 1 + 2x) = 5x^2
2x^2 -6x - 3=0
x= 6 + - sqroot ( 36 + 24) / 4
x= ( 6+- 7.746) / 4= 3.43 m
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.