The specific heat at constant volume of the water vapor (M = 18 g / mol) is cv =

Question

The specific heat at constant volume of the water vapor (M = 18 g / mol) is cv = 2.5 kJ / (kg · K). Determine the specific heat at constant pressure. B.) The specific heat at constant air pressure (M = 29g / mol) is cp = 1kJ / (kg • K). Determine specific heat at constant volume. It is assumed that water vapor and air behave like perfect gases. Answer: a.) 2.96 kJ/(kg•K) b.) 0.713 kJ/(kg•K) The specific heat at constant volume of the water vapor (M = 18 g / mol) is cv = 2.5 kJ / (kg · K). Determine the specific heat at constant pressure. B.) The specific heat at constant air pressure (M = 29g / mol) is cp = 1kJ / (kg • K). Determine specific heat at constant volume. It is assumed that water vapor and air behave like perfect gases. Answer: a.) 2.96 kJ/(kg•K) b.) 0.713 kJ/(kg•K) The specific heat at constant volume of the water vapor (M = 18 g / mol) is cv = 2.5 kJ / (kg · K). Determine the specific heat at constant pressure. B.) The specific heat at constant air pressure (M = 29g / mol) is cp = 1kJ / (kg • K). Determine specific heat at constant volume. It is assumed that water vapor and air behave like perfect gases. Answer: a.) 2.96 kJ/(kg•K) b.) 0.713 kJ/(kg•K)

Explanation / Answer

1) Cp = Cv + R

= 2.5 kJ/kgK + 8.3*1/18 kJ/kgK

= 2.96 kJ/kgK

2) Cv = Cp - R

= 1 - 8.3/29

= 0.713 kJ/kgK

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