The space shuttle uses the oxidation of methyl hydrazine, N2H3CH3(l), for propul

Question

The space shuttle uses the oxidation of methyl hydrazine, N2H3CH3(l), for propulsion. The oxidation proceeds by the following reaction: 5N2O4(g) + 4N2H3CH3(l) --> 12H2O(g) + 9N2(g) + 4CO2(g) The standard enthalpies of formation are: methyl hydrazine +54 kJ/mol dinitrogen tetroxide +9.2 kJ/mol water (g) -242 kJ/mol carbon dioxide -394 kJ/mol Determine the amount of heat generated by the shuttle,in kilojoules, if it is carrying 608.0 kg of methyl hydrazine in its thruster. Assume that methyl hydrazine is the limiting reactant.

Explanation / Answer

Not sure but I think it goes something like this, here'sthe enthalpy of the reaction.

Let UNITs guide you; always USE THEM in your calculation to preventerrors

___5 N2O4(l) + 4 N2H3CH3(l) ------> 12 H2O(g) + 9 N2(g) + 4CO2(g)
dHf -35.05___dHf = -85.39kJ/mole____-241.95_____0_______-39…kJ/mole

dH rxn = sum(dHf product*coeff) - sum(dHf reactant*coeff)

dHrxn = [12*(-241.95) + 9*0 + 4*(-393.51)] - [5*(-35.05) +4*(-85.39)] = ?? (LOTS OF ENERGY)

Plug and SOLVE (this should give you the answer you need togenerate)
Hope this helps~Please Rate!

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