The figure shows a rigid assembly of a thin hoop (of mass m = 0.19 kg and radius

Question

The figure shows a rigid assembly of a thin hoop (of mass m = 0.19 kg and radius R = 0.11 m) and a thin radial rod (of length L = 2R and also of mass m = 0.19 kg). The assembly is upright, but we nudge it so that it rotates around a horizontal axis in the plane of the rod and hoop, through the lower end of the rod. Assuming that the energy given to the assembly in the nudge is negligible, what is the assembly's angular speed about the rotation axis when it passes through the upside-down (inverted) orientation?

Explanation / Answer

Here ,

let the final angular speed is w

for the moment of inertia of assembly

I = m * R^2 + m * (3R)^2 + m * (2R)^2/3

I = 34/3 * 0.19 * 0.11^2

I = 0.0261 Kg.m^2

Using conservation of energy

0.5 * 0.0261 * w^2 = 0.19 * 9.8 * (6 * 0.11 + 0.11)

solving for w

w = 10.5 rad/s

the angular speed of the assembly is 10.5 rad/s

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