A 16.3 kg person climbs up a uniform 137 N ladder. The upper and lower ends of t
ID: 1988221 • Letter: A
Question
A 16.3 kg person climbs up a uniform 137 N
ladder. The upper and lower ends of the ladder rest on frictionless surfaces. The bottom
of the ladder is fastened to the wall by a horizontal rope that can support a maximum tension of 116 N . The angle between the horizontal and the ladder is 52.
A) Find the tension in the rope when the person is one-third of the way up the ladder. The acceleration of gravity is 9.8 m/s2. Answer in units of N
B)Find the maximum distance dmax the person can climb up the ladder before the rope
breaks. Answer in units of m
I really need help with part 2! for part 1 i got 95.11 N. but i used a different process and i dont know how to get part 2. it would be great if someone can help!! I need this question for extra credit! thank you so much!
A 16.3 kg person climbs up a uniform 137 N ladder. The upper and lower ends of the ladder rest on frictionless surfaces. The bottom of the ladder is fastened to the wall by a horizontal rope that can support a maximum tension of 116 N . The angle between the horizontal and the ladder is 52?. A) Find the tension in the rope when the person is one-third of the way up the ladder. The acceleration of gravity is 9.8 m/s2. Answer in units of N B)Find the maximum distance dmax the person can climb up the ladder before the rope breaks. Answer in units of m I really need help with part 2! for part 1 i got 95.11 N. but i used a different process and i dont know how to get part 2. it would be great if someone can help!! I need this question for extra credit! thank you so much!
Explanation / Answer
Let the normal rxn by wall is N1 AND BY FLOOR IS N2
balancing force in x direction
T = N1
for the 1st part we have to just do total moment about bottom point to get N1.and tension will be equal to this normal rxn.
for the second part we have to take tension as its maximum value which is given in question and then put total moment equal to 0 about bottom point .normal rxn from wall be equal to tension ,and from this we will get the position of man.
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