A 9.0×10-2- ice cube at 0.0 is dropped into a Styrofoam cup holding 0.35 of wate

Question

A 9.0×10-2- ice cube at 0.0 is dropped into a Styrofoam cup holding 0.35 of water at 13C?

Part A

Find the final temperature of the system. Assume the cup and the surroundings can be ignored.

Express your answer using one significant figure.















=








Part B

Find the amount of ice (if any) remaining.

Express your answer using two significant figures.















=












Part C

Find the initial temperature of the water that would be enough to just barely melt all of the ice?

find the full answers don't just give me equations to solve:

Explanation / Answer

Mass of ice M = 9.0×10 -2 kg
Initial tmeperature of ice t = 0 o C Mass of water m = 0.35 kg Initial tmeprature of water t ' = 13 o C Heat released by water when it comes from 13 o C to 0 o C is Q = m C ( 13-0) Where C = Specific heat of water                 = 4186 J / kg o C Substitute values we get Q = 19046.3 J Amout of heat required to melt M ice Q ' = ML Where L = Latent heat of fusion                 = 3.34 x 10 5 J / kg So, Q ' = 30139.2 J Q < Q ' . All ice is not melted. So, Final temperature of the system T = 0 o C (b). Required tempertaure of water t " = Q ' / mC                                                            = 20.57 o C i.e., if the temeprature of the water is 20.57 o C then total ice is melted

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