A 9 V battery can be connected through a 1000 ohm resistor and a switch to a par

Question

A 9 V battery can be connected through a 1000 ohm resistor and a switch to a parallel combination of a resistor, R = 1000 ohms , a capacitor, C = 300 mF, and an inductor, L = 500 mH. The switch has been open for a very long time.



A. Just after the switch is closed, find the voltage across and current through each of the three circuit elements, R, C and L.

B. A long time after the switch is closed, find the voltage across and current through each of the three circuit elements, R, C and L.

C. The switch is left closed for a long time and then is reopened. Find the current through each of the three circuit elements, R, C and L just after this is done. (You don't have to provide the voltages.)

Explanation / Answer

A) Just after the switch is closed inductor-- doesn't let any current to flow.

capacitor-- acts like zero resistance wire.

resistor -- does not change.

so it means all current will flow through capacitor at the very begining.

I(R)=0, I(L)= 0, I(C)= V/1000 = 0.009 A.

B) After long time

capacitor-- doesn't let any current to flow.

inductor -- acts like zero resistance wire.

resistor -- does not change.

so it means all current will flow through inductor after long time.

I(R)=0, I(C)= 0, I(L)= V/1000 = 0.009 A.

C) It becomes circiut of paralel resistor, capacitor and inductor.Inductor has current I at time t=0. Capacitor has no charge. resistor has no current. Then

capacitor-- acts like zero resistance wire.(Because of no charge in)

So at the very beginning of opening the switch

inductor and capacitor have current of V/1000 = 0.009A

resistor has no current.

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