A 9 V battery is hooked up to two resistors in series. One has a resistance of 5

Question

A 9 V battery is hooked up to two resistors in series. One has a resistance of 5 ohms, and the other has aresistance of 10 ohms. Several locations along the circuit are marked with letters, as shown in thefigure. If the voltage is zero at the negative terminal of the battery, the voltage at location B is ___.explain

A) zero. B) 4.5 V.C) greater than 4.5 V. D) less than 4.5 V.

A 9 V battery is hooked up to two resistors in series. One has a resistance of 5 ohms, and the other has aresistance of 10 ohms. Several locations along the circuit are marked with letters, as shown in thefigure. If the voltage is zero at the negative terminal of the battery, the voltage at location B is ___.explain A) zero. B) 4.5 V.C) greater than 4.5 V. D) less than 4.5 V.

Explanation / Answer

V=IR
thus the current running through the circuit is 9/(5+10)=0.6
the voltage drop through the 5ohm resistor is 0.6*5=3
thus the voltage at point B is 9-3=6V
answer>> C

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