4) At a certain location, the horizontal component of a planet\'s magnetic field

Question

4) At a certain location, the horizontal component of a planet's magnetic field is observed to be 6.5 x 10^-5 Tesla. The magnetic field has a field inclination of 65 degree. Determine the magnitude of the vertical component of the planet's magnetic field.

the answer is 13.94 x 10^-5 Tesla, why???


5) A small parallel plate capacitor with circular plates, radius = 0.002 meter, is oriented such that one plate is directly above the other plate and the y axis is perpendicular to both plates and passes through the center of the plates. The displacement current is directed in the positive y direction. An observer is located at the origin of the coordinate system and is looking up the y axis. This observer would describe the pattern of magnetic field lines due to the displacement current as

the answer is 'circular with center on the y axis, and directed clockwisw.'
please explain something for the answer.

Explanation / Answer

The horizontal component of the field is

            Bx = B cos 65

   6.5x10^-5 = B cos 65

       B = 15.38x10^-5

The vertical component is given as

       By = B sn 65

          = (15.38x10^-5) sin 65

          = 13.94x10^-5 T

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For a displacment current along the positive y axis the force on the particle would be into the page for a parallel plate capacitor placed along the y axis.

The direction of the current is towwards the positve y axis and the force is into the page and direction of the field is in clock wise direction

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