On an old-fashioned rotating piano stool, a woman sits holding a pair of dumbbel

Question

On an old-fashioned rotating piano stool, a woman sits holding a pair of dumbbells at a distance of 0.600 from the axis of rotation of the stool. She is given an angular velocity of 3.00 , after which she pulls the dumbbells in until they are only 0.200 distant from the axis. The woman's moment of inertia about the axis of rotation is 5.00 and may be considered constant. Each dumbbell has a mass of 5.00 and may be considered a point mass. Neglect friction.What is the initial angular momentum of the system?

Explanation / Answer

What is the initial angular momentum of the system? --->add the woman's I to I of dumblells (m*r^2 = 10.0 * (0.600)^2) then momentum = I * omega (3.00 rad/s)

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