Scientists in the laboratory set up a uniform electric field of -2.300×103 V/m a

Question

Scientists in the laboratory set up a uniform electric field of -2.300×103 V/m along the y-axis. In this same region, B=4.000×10-3 T along the z-axis. A proton moves at speed 5.900×106 along the x-axis. The answers to the following questions are vectors. Include the three components in the appropriate boxes for the answers.

What are the force components on the proton as measured in the laboratory frame?

i+ j+ k

What are the E'-Field components as seen in the proton's rest frame?

i+ j+ k

What are the B'-Field components as seen in the proton's rest frame?

i+ j+ k

What are the force components on the proton as measured in the proton's rest frame?

i+ j+ k

Explanation / Answer

force due to electric field = -2.300 * 10^3 j
force due to magnetic field =V X B =(5.9x10^6 i) 4 x 10^(-3) k  = -2.36x10^4 j

so force component on proton = - 4.66x10^4 J (along negative y axis)

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