A woman is skating to the right with a speed of 12.0 m/s when she is hit in the

Question

A woman is skating to the right with a speed of 12.0 m/s when she is hit in the stomach by a giant snowball moving to the left. The mass of the snowball is 2.00 kg, its speed is 25.0 m/s and it sticks to the woman's stomach. If the mass of the woman is 60.0 kg, what is her speed after the collision?
a) 10.8 m/s
b) 11.2 m/s
c) 12.4 m/s
d) 12.8 m/s

What I have done is...
Conservation of Momentum:

mfwV2fw + mfsV2fs = miwV2iw + misV2is
(mfw + mfs)V2f = miwV2iw + misV2is

then after isolating for V2f I get 12.62m/s......and the answer is 10.8m/s

Please Help!

Explanation / Answer

usin the conservation of momnetum

60(12 ) - 2(25) = ( 60+2)V

where V is the velocity of combined mass

670 /62 =V

V = 10.8 m/s apprx

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