A woman can see clearly with her right eye only when objects are between 41 cm a

Q: A woman can see clearly with her right eye only when objects are between 41 cm a

for upper part object distance s = infinity image distance s' = -120 from lens equation 1/s + 1/s' = 1/f 1/infinity - 1/120 = 1/f f = -120 cm power = 1/f(in m) Pupper = -1/1.2 = -0.83 D ++++++++ for lower part object distance s = 25 cm image distance s' = -41 cm 1/s + 1/s' = 1/f 1/25 - 1/41 = 1/f f = 64.1 cm Plower = 1/f(in m) = 1/0.641 = + 1.56 D Pupper , Plower = -0.833 , 1.56 D

ID: 1453651 • Letter: A

Question

A woman can see clearly with her right eye only when objects are between 41 cm and 120 cm away. Prescription bifocals should have what powers so that she can see distant objects clearly (upper part) and be able to read a book 25 cm away (lower part) with her right eye? Assume that the glasses will be 2.0 cm from the eye. Express your answers using two significant figures separated by a comma. P_upper part, P_lower part = Term 2: Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures.

Explanation / Answer

for upper part

object distance s = infinity

image distance s' = -120

from lens equation

1/s + 1/s' = 1/f

1/infinity - 1/120 = 1/f

f = -120 cm

power = 1/f(in m)

Pupper = -1/1.2 = -0.83 D

++++++++

for lower part

object distance s = 25 cm

image distance s' = -41 cm

1/s + 1/s' = 1/f

1/25 - 1/41 = 1/f

f = 64.1 cm

Plower = 1/f(in m) = 1/0.641 = + 1.56 D

Pupper , Plower = -0.833 , 1.56 D <<<<------------answer

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A woman can see clearly with her right eye only when objects are between 41 cm a

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