A fish takes the bait and pulls on the line with a force of 2.8 . The fishing re

Question

A fish takes the bait and pulls on the line with a force of 2.8 . The fishing reel, which has a friction clutch that exerts a restraining torque of 0.045 , is a cylinder of radius 0.055 and mass 0.82 .

What is the angular acceleration of the fishing reel?

How much line does the fish pull from the reel in 0.30 ?

I already have the angular acceleration (88rads/s^2). Please help with how much line it pulls.

Explanation / Answer

theta = 1/2 * angular acceleration * t^2 = 1/2 * 88*.3^2 = 3.96 radians; ==> 3.96/(2*pi) revolutions = 0.630253575 revolutions; length of reel = 0.630253575*(2*pi*.055) = 0.2178 meters; length of reel pulled by fish = 0.2178 meters

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