Please set this up in steps so I can see how to arrive at the solution...I use t

Question

Please set this up in steps so I can see how to arrive at the solution...I use these questions to study for my exams...So I need to see how the equations used were derived

A skater has rotational inertia 4.2 kg*m2 and his fists held to his chest and 5.7 kg*m2 with his arms outstretched. The skater is spinning at 3.0 rev/s while holding a 2.5 kg weight in each outstretched hand; the weights are 76cm from his rotation axis.

If he pulls his hands in to his chest so they are essentially on his rotational axis, how fast will he be spinning?

Explanation / Answer

According to congservation of angular momentum, momentum before and after is same.             Li = Lf         I1 1 = I2 2       [ 5.7 + 2 (2.5) (0.76)^2 ] (3 rev /s ) = [ 4.2 ] 2        2 = 6.134 rev /s     or    38.54 rad /s

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