A 51.4-cm diameter disk rotates with a constant angular acceleration of 2.20 rad

Question

A 51.4-cm diameter disk rotates with a constant angular acceleration of 2.20 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time.
(a) Find the angular speed of the wheel at t = 2.30 s.
rad/s


(b) Find the linear velocity and tangential acceleration of P at t = 2.30 s.
linear velocity: m/s
tangential acceleration: m/s2

(c) Find the position of P (in degrees, with respect to the positive x-axis) at t = 2.30s.
: °

Explanation / Answer

a)

wf=wi+*t

=0+2.2*2.3

=5.06 rad/sec

b)v=w*r

=5.06*.514/2

linear velocity =1.3004 m/s

tangentail acc=*r

=2.2*.514/2

=.05654 m/s^2

c)=*t*t/2

=2.2*2.3*2.3/2

=5.819 rad

=166.7 degree

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.