A traveler pushes a loaded luggage cart along a straight line in an airport. She

Question

A traveler pushes a loaded luggage cart along a straight line in an airport. She pushes the cart along the line of the cart's motion, and the cart is moving at a constant velocity 1.5 m/s. The total mass of the cart and luggage is 47 kg.


(a) If the static friction coefficient s = 0.4 and the kinetic friction coefficient k = 0.3 between the cart and the airport floor, how much force is she applying on the cart?


(b) For the same friction coefficients (s = 0.4 and k = 0.3), what is the power dissipated by the friction?

Explanation / Answer

Given data : k = 0.3   ; s = 0.4 ; v = 1.5 m/s

a) move at constant velocity so acceleration = 0

F = 0

F - k.mg = 0

F = k.m.g = 0.3(47)(9.8) = 138.18 N

b) P = fs.s/t = fs.v = (138.18).(1.5) = 207.27 W

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