A laboratory magnet (see the figure) with a field B = 0.25 T over an effective a

Question

A laboratory magnet (see the figure) with a field B = 0.25 T over an effective area 16.0 cm in diameter exerts a force on a current-carrying wire that crosses between the pole faces at right angles to the field. The current in the wire is 9.0 A.

1) What is the magnitude of the force on the wire?

2) What is the direction of the force? (left, right, up, down, front, back)

(please show work! thanks!)

Figure 19.14 Example 19.3: A current-carrying Wire in a magnetic field A laboratory magnet (see the figure) with a field B = 0.25 T over an effective area 16.0 cm in diameter exerts a force on a current-carrying wire that crosses between the pole faces at right angles to the field. The current in the wire is 9.0 A. 1) What is the magnitude of the force on the wire? 2) What is the direction of the force? (left, right, up, down, front, back)

Explanation / Answer

are you sure UP is not right ? because if you think logically it has to be either UP or DOWN . Magnetic Force , Current , Magnetic Field have to be perpendicular to each other. F = q(v x B ) ( In a cross product , the resultant force has to be at 90 degrees to the velocity and field. It has to be in the upward direction. Try using another method such as fleming's left hand rule. There too, you get upward direction of force. If it were at left or right, then there would be no magnetic force acting at all F = q (v x B) = 0

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.