Three people poll simultaneously on a stubborn donkey Jack pulls eastward with a

Question

Three people poll simultaneously on a stubborn donkey Jack pulls eastward with a force of 73 7 N. Jill pulls with 65 5 N in the northeast direction, and Jane pulls to the southeast with 113 N (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn?) Find the magnitude of the net force the people exert on the donkey. What is the direction of the net force? Express this as the angle from the east direction between 0 degree and 90 degree , with a positive sign for north of east and a negative sign for south of east

Explanation / Answer

Forces f = 73.7 i            f ' = 65.5 cos 45 i + 65.5 sin 45 j               = 46.31 i + 46.31 j          f " = 113 cos 45 i + 11 sin 45 ( -j)              = 79.9 i - 79.9 j Net force F = f + f ' + f "                     = 73.7 i +46.31 i + 46.31 j+ 79.9 i - 79.9 j                     = 199.91 i - 33.59 j Magnitude of F = [ 199.91 2 + (-33.59) 2 ]                          = 202.71 N Let F makes an angle with east along south then tan = 33.59 / 199.91                                                                                   = 9.53 o Forces f = 73.7 i            f ' = 65.5 cos 45 i + 65.5 sin 45 j               = 46.31 i + 46.31 j          f " = 113 cos 45 i + 11 sin 45 ( -j)              = 79.9 i - 79.9 j Net force F = f + f ' + f "                     = 73.7 i +46.31 i + 46.31 j+ 79.9 i - 79.9 j                     = 199.91 i - 33.59 j Magnitude of F = [ 199.91 2 + (-33.59) 2 ]                          = 202.71 N Let F makes an angle with east along south then tan = 33.59 / 199.91                                                                                   = 9.53 o

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.