4452546 ing.com/ibiscms/mod/ibis/view.php?id L Wholesale BI B1 Wholesale B Made

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4452546 ing.com/ibiscms/mod/ibis/view.php?id L Wholesale BI B1 Wholesale B Made in the USA - A psycholo -Math Book OSchoorships = Brixton Wheeler ll w Sapling Learning two parents, a father with the genotype AaBbCcDdee and a mother with the genotype wanted to have children. Assume each locus follows Mendelian inheritance patterns for What proportion of the offspring will have each of the following characteristics? Round your answers to two decimal places same genotype as the father same genotype as the mother Number Number phenotypically resemble the father phenotypically resemble the mother Number Number phenotypically resemble neither parent Number Hint O Previous Check Answer NextEx about us careers privacy oolicv terms of usecontact us

Explanation / Answer

As per Mendelian Laws of Inheritance (Segregation, Independent Assortment and Inheritance), we get:
Father's genotype = AaBbCcDdee
Mother's genotype = aabbCcDDEe
Father's sex cells alleles = (A/a)(B/b)(C/c)(D/d)(e/e)
Mother's sex cells alleles = (a/a)(b/b)(C/c)(D/D)(E/e)
Deconstructing this gene-by-gene, we get:
Probablity of dominant phenotype (allele expressed in uppercase) versus probablity of recessive phenotype (allele expressed in lowercase)

Aa x aa = Aa, Aa, aa, aa = PA is 1/2 and Pa is 1/2
Bb x bb = Bb, Bb, bb, bb = PB is 1/2 and Pb is 1/2
Cc x Cc = CC, Cc, cC, cc = PC is 3/4 and Pc is 1/4
Dd x DD = DD, DD, dD, dD = PD is 1 and Pd is 0
ee x Ee = eE, eE, ee, ee = PE is 1/2 and Pe is 1/2

Same genotype as father = AaBbCcDdee = (1/2)*(1/2)*(1/2)*(1/2)*(1/2) = 1/32
Same genotype as mother = aabbCcDDEe = (1/2)*(1/2)*(1/2)*(1/2)*(1/2) = 1/32
Phenotypically resemble the father = ABCDe = (1/2)*(1/2)*(3/4)*(1)*(1/2) = 3/32
Phenotypically resemble the mother = abCDE = (1/2)*(1/2)*(3/4)*(1)*(1/2) = 3/32
Phenotypically resemble neither parent = 1 - (Phenotypically resemble the father + Phenotypically resemble the mother) = 1 - ( 3/32 + 3/32 ) = 26/32 = 13/16

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