Just need part C answered. A variable capacitor with a range from 20 pF to 415 p
ID: 1949795 • Letter: J
Question
Just need part C answered.A variable capacitor with a range from 20 pF to 415 pF is used with a coil to form a variable-frequency LC circuit to tune the input to a radio.
(a) What ratio of maximum frequency to minimum frequency that can be obtained with such a capacitor?
4.55
(b) If this circuit is to obtain frequencies from 0.54 MHz to 1.60 MHz, the ratio computed in (a) is too large. By adding a capacitor in parallel to the variable capacitor, this range can be adjusted. What capacitance should be added to obtain the desired frequency range?
30.64
(c) What inductance should the coil have to obtain the desired frequency range?
Explanation / Answer
(c) ? = 2pf = v(1/LC) (2pf)^2 *C = 1/L L = 1/(2pf)^2 *C = 1/ [(2*3.14*1.6*10^6)^2 * 50.64*10^-12] =1.95*10^-4 H = 0.195 mH 50.64pF = 30.64pF + 20pF
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