Just need answer to part d....all others are correct Two masses (mA= 3 kg, mB= 6

Question

Just need answer to part d....all others are correct

Two masses (mA= 3 kg, mB= 6 kg) are attached to a (massless) meter stick, at the 0 and 75 cm marks, respectively.

a.) Where is the center of mass of this system?

50 cm, from mass A.

b.) The system is then hung from a string, so that it stays horizontal. Where should the string be placed?

50 cm, from mass A.

c.) Now, if mass B was removed, how much force would need to be exerted at the 100 cm mark in order to keep the meter stick level*?

size: 29.4 N, dir: downwards

d.) Now, if mass B was removed, and no additional force was supplied, calculate the size of the angular acceleration of the meter stick at that instant*. rad/s2

Explanation / Answer

Torque around axis passing through c.m in horizontal directiona nd perpendicular to stick:

=r*F=I*(angular accleration)

0.50*9.8*3= 3*0.5*0.5*(angular accleration) /*I of mass around an axis=m*r2*/

angular accleration=0.50*9.8/(0.5*0.5) =19.6 rad/s2    dir: downward from mass 3 kg in vertical circle

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