It says to find the power \"supplied\" by the VCCS. I found id=4Vc=4(-2)= -8A. H

Question

It says to find the power "supplied" by the VCCS.

I found id=4Vc=4(-2)= -8A.

However, when trying to find the power of the VCCS, I am confused because......based on passive and non-passive sign convention, how do I know when to do this:

p = -vi ?

VS

p = vi ?

Can you please explain "CLEARLY"?

thanks!

It says to find the power supplied by the VCCS. I found id=4Vc=4(-2)= -8A. However, when trying to find the power of the VCCS, I am confused because......based on passive and non-passive sign convention, how do I know when to do this: p = -vi ? VS p = vi ? Can you please explain CLEARLY? thanks!

Explanation / Answer

here the direction of current is indicated away from the junctions means
Id=4Vc =4*2=8A

power

Pd =VdId =8*2.2=17.6 Watts are supplied by the VCCS.

if it is towards the junction then

P=-VdId

here above is the answer

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.