6) A wastewater flow of 8.6 MGD is treated in a wastewater plant having 4 primar
ID: 1920994 • Letter: 6
Question
6) A wastewater flow of 8.6 MGD is treated in a wastewater plant having 4 primary sedimentation tanks. The SS concentration of the wastewater is 265 mg/l and the flow is split between the 4 sedimentation tanks as follows: Three of the tanks (tanks#1,#2,and #3) handle is 2.0 MGD while the fourth tank (tank#4) handles the remaining 2.6 MGD. Tanks #2 and #3 have a removal efficiency of 60%, tank#1 has a removal efficiency of 55% and tank#4 has a removal efficiency of 66%.
a) How many dry tons of sludge is produced in one day by tanks #2 and #3 combined?
b) How many dry tons of sludge is produced in one day by tank #4/
c) How many dry tons of sludge is produced in one day by all four tanks combined?
Explanation / Answer
1. Dry tons of sludge is produced in one day by tanks #2 and #3 combined = 265*10-9*4*3.785*106*0.6 = 2.407 dry tons/day
2. Dry tons of sludge is produced in one day by tank #4=265*10-9*2.6*3.785*106*0.66 = 1.7211 tons/day
3. Dry tons of sludge is produced in one day by all tank =0.55*2*106*265*10-9*3.785+ 2.407+1.7211 =5.23 tons/day
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